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6p^2-9p-14=0
a = 6; b = -9; c = -14;
Δ = b2-4ac
Δ = -92-4·6·(-14)
Δ = 417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{417}}{2*6}=\frac{9-\sqrt{417}}{12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{417}}{2*6}=\frac{9+\sqrt{417}}{12} $
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